Write a program to create a square matrix of type integer of size ‘n’, where the value of ‘n’ is input by the user. Now fill the matrix with natural numbers in circular/spiral fashion in clockwise order, starting from index [0, 0], and display the generated matrix.

**Example:**

INPUT:

N = 5

OUTPUT:

1 2 3 4 5

16 17 18 19 6

15 24 25 20 7

14 23 22 21 8

13 12 11 10 9

```
import java.io.*;
class CircularFill{
public static void main(String args[])throws IOException{
BufferedReader br = new BufferedReader(new InputStreamReader(System.in));
System.out.print("N = ");
int n = Integer.parseInt(br.readLine());
int a[][] = new int[n][n];
int value = 1;
int row1 = 0;
int col1 = 0;
int row2 = n - 1;
int col2 = n - 1;
int i = 0;
int j = 0;
while(value <= n * n){
for(i = col1; i <= col2; i++)
a[row1][i] = value++;
for(i = row1 + 1; i <= row2; i++)
a[i][col2] = value++;
for(i = col2 - 1; i >= col1; i--)
a[row2][i] = value++;
for(i = row2 - 1; i >= row1 + 1; i--)
a[i][col1] = value++;
col1++;
col2--;
row1++;
row2--;
}
System.out.println("Generated Matrix:");
for(i = 0; i < n; i++){
for(j = 0; j < n; j++)
System.out.print(a[i][j] + "\t");
System.out.println();
}
}
}
```

Sir,a program is given which states that:

WAP in java to create a 2D array of size n x n (n >2 & n < 10).Now fill the numbers in a circular fashion (anti-clockwise) with natural numbers from 1 to n^2,as illustrated below:

E.g.if n=5,n^2=25,then the array is filled as:

21 20 19 18 17

22 7 6 5 16

23 8 1 4 15

24 9 2 3 14

25 10 11 12 13

Here is the link to the solution for generating spiral matrix in anticlockwise fashion.