## Multiple Choice Questions

- When the statements are repeated sequentially for a number of times in a program, the construct is known as:
**(a) iteration**

(b) sequence

(c) selection

(d) none - Which of the following statement is an exit-controlled loop?

(a) for

(b) while**(c) do-while**

(d) if-else - Which of the following loop does not execute even once if the condition is false in the beginning?

(a) do-while**(b) while****(c) for**

(d) nested loop - To execute a loop 10 times, which of the following statement satisfies?

(a) for(i = 6;i <= 26; i = i + 2)**(b) for(i = 3; i <= 30; i = i + 3)**

(c) for(i = 0; i < 10; i = i++)

(d) all of the above - Which of the following statement uses multiple branches?

(a) loop

(b) continue**(c) switch**

(d) break - Which of the following loop checks the condition first and then execution begins?

(a) do-while

(b) do**(c) while loop****(d) for** - To find the sum of whole numbers up to 10, a loop runs:

(a) once

(b) ten times**(c) eleven times**

(d) any number of times - How many times the loop: for(i = 1;; i++) will execute, if there is no statement to terminate the loop?

(a) 1

(b) 0**(c) infinite**

(d) none - Which of the following statements uses a case called default?

(a) do-while

(b) while**(c) switch**

(d) all of the above - A loop statement is given as:

for(i = 10; i < 10; i++){

statement

}

For how many times will the given loop statement be executed?**(a) never**

(b) 1 time

(c) 10 times

(d) infinite

## Answer the following questions:

**What do you understand by iterative process? How can it be resolved by using loop?**

It is a construct in which a statement or a set of statements are repeatedly executed till the condition is satisfied.

It can be resolved by using loops because it allows us to easily specify what task needs to be executed and for how many times.**Explain for loop with an example.**

The for loop is an entry-controlled loop which is suitable when the number of iterations is fixed.**Example:**

for(i = 1; i <= 10; i++){

System.out.println(“Google Pay”);

System.out.println(“Money made simple, by Google”);

}**Name the different types of loop statements.**

Different types of loop statements are:

a) for loop

b) while loop

c) do-while loop**What are the parameters needed to create a for loop?**

Following are the parameters needed to create a for loop:

a) Initial value for the counter variable.

b) Test condition to terminate the loop at a certain point.

c) Update expression to modify the counter variable after each iteration.

d) Loop body to be executed in each iteration.**Define the following with their constructs:****(a) Entry-controlled loop:**Condition is checked before executing the loop body. Constructs: for loop and while loop.**(b) Exit-controlled loop:**Condition is checked after executing the loop body. Construct: do-while loop.**Write down the general format of:****(a) for loop**

for(initial value; test condition; update){

task

}**(b) do-while loop**

do{

task

}while(test condition);**(c) while loop**

while(test condition){

task

}**What is the purpose of using:****(a) break statement:**It is used for forceful termination of a loop block.**(b) continue statement:**It is used to skip the current iteration of the loop, and move to the next iteration.**What do you understand by inter-conversion of loops?**

Inter-conversion of loops is about converting one form of repetitive structure to another form to model our program logic as per our convenience.**What are the different ways to inter-convert the loops? Name them.**

Following are the different ways to inter-conversion of loops:

a) for loop to while loop

b) for loop to do-while loop

c) do-while loop to while loop

d) do-while loop to for loop

e) while loop to do-while loop

f) while loop to for loop**Define the following:****(a) Finite loop:**Loop in which the statements run for a fixed number of times.**(b) Delay loop:**Loop that is used to create a delay in the execution by creating a null loop.**(c) Infinite loop:**Loop in which a looping structure will never come to an end, created by omitting one or more parameters.**(d) Null loop:**Loop which doesn’t include any statement to be repeated.**Distinguish between:****(a) for and while loop**

The for loop is a suitable choice when the number of iterations is fixed, whereas the while loop is a suitable choice when the number of iterations is not fixed.**(b) while and do-while loop**

The while loop is entry-controlled, whereas the do-while loop is exit-controlled.**State one difference and one similarity between while and do-while loop.****Similarity:**Both while and do-while loops are used when the number of iterations is not fixed.**Dissimilarity:**The while loop is entry-controlled, but the do-while loop is exit-controlled.**State one similarity and one difference between while and for loop.****Similarity:**Both while and for loops are entry-controlled loops.**Dissimilarity:**The for loop is a suitable choice when the number of iterations is fixed. The while loop is a suitable choice when the number of iterations is not fixed.**Give two differences between step loop and continuous loop.****Step loop**is a system of creating a loop where the control variable is updated by a given value after each iteration. The loop starts with an initial value, repeats execution of the statements by updating the value with the given step.**Continuous loop**is a type of looping structure in which the control variable is updated only by 1 after each iteration. The loop is terminated as soon as the control variable exceeds the last limit.

## Java Programs:

**Question 1**: Write the programs in Java to display the first ten terms of the following series:

a) 1, 4, 9, 16, …

b) 1, 2, 4, 7, 11, …

c) 3, 6, 9, 12, …

d) 4, 8, 16, 32, …

e) 1.5, 3.0, 4.5, 6.0, …

f) 0, 7, 26, …

g) 1, 9, 25, 49, …

h) 4, 16, 36, 64, …

i) 0, 3, 8, 15, …

j) 24, 99, 224, 399, …

k) 2, 5, 10, 17, …

```
class Series1{
public static void main(String args[]){
for(int i = 1; i <= 10; i++)
System.out.print(i * i + "\t");
System.out.println();
}
}
```

```
class Series2{
public static void main(String args[]){
int value = 1;
for(int i = 1; i <= 10; i++){
System.out.print(value + "\t");
value += i;
}
System.out.println();
}
}
```

```
class Series3{
public static void main(String args[]){
for(int i = 1; i <= 10; i++)
System.out.print((i * 3) + "\t");
System.out.println();
}
}
```

```
class Series4{
public static void main(String args[]){
int value = 4;
for(int i = 1; i <= 10; i++){
System.out.print(value + "\t");
value *= 2;
}
System.out.println();
}
}
```

```
class Series5{
public static void main(String args[]){
double value = 1.5;
for(int i = 1; i <= 10; i++){
System.out.print(value + "\t");
value += 1.5;
}
System.out.println();
}
}
```

```
class Series6{
public static void main(String args[]){
for(int i = 1; i <= 10; i++){
int term = (int)(Math.pow(i, 3) - 1);
System.out.print(term + "\t");
}
System.out.println();
}
}
```

```
class Series7{
public static void main(String args[]){
int value = 1;
for(int i = 1; i <= 10; i++){
int term = value * value;
System.out.print(term + "\t");
value += 2;
}
System.out.println();
}
}
```

```
class Series8{
public static void main(String args[]){
int value = 2;
for(int i = 1; i <= 10; i++){
int term = value * value;
System.out.print(term + "\t");
value += 2;
}
System.out.println();
}
}
```

```
class Series9{
public static void main(String args[]){
for(int i = 1; i <= 10; i++){
int term = i * i - 1;
System.out.print(term + "\t");
}
System.out.println();
}
}
```

```
class Series10{
public static void main(String args[]){
int value = 5;
for(int i = 1; i <= 10; i++){
int term = value * value - 1;
System.out.print(term + "\t");
value += 5;
}
System.out.println();
}
}
```

```
class Series11{
public static void main(String args[]){
int value = 2;
int add = 3;
for(int i = 1; i <= 10; i++){
System.out.print(value + "\t");
value += add;
add += 2;
}
System.out.println();
}
}
```

**Question 2**: Write a program to input any 50 numbers (including positive and negative) and perform the following tasks:

a) Count the positive numbers.

b) Count the negative numbers.

c) Sum of positive numbers.

d) Sum of negative numbers.

```
import java.io.*;
class Counting{
public static void main(String args[])throws IOException{
BufferedReader br = new BufferedReader(new InputStreamReader(System.in));
int cp = 0;
int cn = 0;
int sp = 0;
int sn = 0;
System.out.print("Enter 50 numbers: ");
for(int i = 1; i <= 50; i++){
int n = Integer.parseInt(br.readLine());
if(n >= 0){
cp++;
sp += n;
}
else{
cn++;
sn += n;
}
}
System.out.println("Number of positive numbers: " + cp);
System.out.println("Sum of positive numbers: " + sp);
System.out.println("Number of negative numbers: " + cn);
System.out.println("Sum of negative numbers: " + sn);
}
}
```

**Question 3**: Write a program to calculate the sum of all odd numbers and even numbers between a range of numbers from m to n (both inclusive) where m < n. Input m and n.

```
import java.io.*;
class Sum{
public static void main(String args[])throws IOException{
BufferedReader br = new BufferedReader(new InputStreamReader(System.in));
int odd = 0;
int even = 0;
System.out.print("M = ");
int m = Integer.parseInt(br.readLine());
System.out.print("N = ");
int n = Integer.parseInt(br.readLine());
if(m < n){
for(int i = m; i <= n; i++){
if(i % 2 == 0)
even += i;
else
odd += i;
}
System.out.println("Sum of positive numbers: " + even);
System.out.println("Sum of negative numbers: " + odd);
}
else
System.out.println("Invalid range!");
}
}
```

**Question 4**: Write a program to enter any 50 numbers and check whether they are divisible by 5 or not. If divisible, then perform the following tasks:

a) Display all the numbers ending with the digit 5.

b) Count those numbers ending with 0.

```
import java.io.*;
class Five{
public static void main(String args[])throws IOException{
BufferedReader br = new BufferedReader(new InputStreamReader(System.in));
int zero = 0;
for(int i = 1; i <= 50; i++){
System.out.print("Number = ");
int n = Integer.parseInt(br.readLine());
if(n % 5 == 0){
if(n % 10 == 5)
System.out.println(n + " ends with 5.");
else
zero++;
}
}
System.out.println("Number of values ending with zero: " + zero);
}
}
```

**Question 5**: Write a program to display all the numbers between m and n input from the keyboard where m < n, m > 0 and n > 0. Check and print the numbers that are perfect square. Example: 25, 36, 49 are perfect square numbers.

```
import java.io.*;
class PerfectSquares{
public static void main(String args[])throws IOException{
BufferedReader br = new BufferedReader(new InputStreamReader(System.in));
int zero = 0;
System.out.print("M = ");
int m = Integer.parseInt(br.readLine());
System.out.print("N = ");
int n = Integer.parseInt(br.readLine());
if(m < n && m > 0 && n > 0){
for(int i = m; i <= n; i++){
System.out.println("Number = " + i);
double s = Math.sqrt(i);
if(s == (int)s)
System.out.println(i + " is a perfect square.");
}
}
else
System.out.println("Invalid range!");
}
}
```

**Question 6**: Write a program to display all the buzz numbers between p and q where p < q. A buzz number is the number which either ends with 7 or is divisible by 7.

```
import java.io.*;
class Buzz{
public static void main(String args[])throws IOException{
BufferedReader br = new BufferedReader(new InputStreamReader(System.in));
System.out.print("p = ");
int p = Integer.parseInt(br.readLine());
System.out.print("q = ");
int q = Integer.parseInt(br.readLine());
if(p < q){
for(int i = p; i <= q; i++){
if(i % 10 == 7 || i % 7 == 0)
System.out.print(i + "\t");
}
System.out.println();
}
else
System.out.println("Invalid range!");
}
}
```

**Question 7**: Write a program to input marks in English, Math and Science of 40 students who have passed ICSE Examination 2019. Now perform the following tasks:

a) Number of students who have secured 95% or more in all the subjects.

b) Number of students who have secured 90% or more in English, Math and Science.

```
import java.io.*;
class Student{
public static void main(String args[])throws IOException{
BufferedReader br = new BufferedReader(new InputStreamReader(System.in));
int math = 0;
int science = 0;
int english = 0;
int all = 0;
for(int i = 1; i <= 40; i++){
System.out.print("Math: ");
int m = Integer.parseInt(br.readLine());
System.out.print("Science: ");
int s = Integer.parseInt(br.readLine());
System.out.print("English: ");
int e = Integer.parseInt(br.readLine());
if(m >= 95 && s >= 95 && e >= 95)
all++;
if(m >= 90)
math++;
if(s >= 90)
science++;
if(e >= 90)
english++;
}
System.out.println("95% or above in all subjects: " + all);
System.out.println("90% or above in Math: " + math);
System.out.println("90% or above in Science: " + science);
System.out.println("90% or above in English: " + english);
}
}
```

**Question 8**: Write a program in Java to find the sum of the given series:**a)** 1 + 4 + 9 + … + 400

```
class Sum1{
public static void main(String args[]){
int s = 0;
for(int i = 1; i <= 20; i++)
s += i * i;
System.out.println("Series sum: " + s);
}
}
```

**b)** 1 + 1/2 + 1/3 + … + 1/20

```
class Sum2{
public static void main(String args[]){
double s = 0.0;
for(int i = 1; i <= 20; i++)
s += 1.0 / i;
System.out.println("Series sum: " + s);
}
}
```

**c)** 1 + 1/3 + 1/5 + … + 1/19

```
class Sum3{
public static void main(String args[]){
double s = 0.0;
for(int i = 1; i <= 19; i += 2)
s += 1.0 / i;
System.out.println("Series sum: " + s);
}
}
```

**d)** 1/2 + 2/3 + 3/4 + … + 19/20

```
class Sum4{
public static void main(String args[]){
double s = 0.0;
for(double i = 1.0; i <= 19.0; i++)
s += i / (i + 1);
System.out.println("Series sum: " + s);
}
}
```

**e)** 2 – 4 + 6 – 8 + … – 20

```
class Sum5{
public static void main(String args[]){
int s = 0;
int sign = 1;
for(int i = 2; i <= 20; i += 2){
s += i * sign;
sign *= -1;
}
System.out.println("Series sum: " + s);
}
}
```

**f)** (1 * 2) + (2 * 3) + … + (19 * 20)

```
class Sum6{
public static void main(String args[]){
int s = 0;
for(int i = 1; i <= 19; i++)
s += i * (i + 1);
System.out.println("Series sum: " + s);
}
}
```

**Question 9**: Write a program to input a number and count the number of digits. The program further checks whether the number contains odd number of digits or even number of digits.

```
import java.io.*;
class Digits{
public static void main(String args[])throws IOException{
BufferedReader br = new BufferedReader(new InputStreamReader(System.in));
int count = 0;
System.out.print("Enter the number: ");
int num = Integer.parseInt(br.readLine());
if(num == 0)
count = 1;
for(int i = num; i > 0; i /= 10)
count++;
if(count % 2 == 0)
System.out.println("It has even number of digits.");
else
System.out.println("It has odd number of digits.");
}
}
```

**Question 10**: Write a program to input a number and display the new number after reversing the digits of the original number. The program also displays the absolute difference between the original number and the reversed number.

```
import java.io.*;
class Reverse{
public static void main(String args[])throws IOException{
BufferedReader br = new BufferedReader(new InputStreamReader(System.in));
int rev = 0;
System.out.print("Enter the number: ");
int num = Integer.parseInt(br.readLine());
for(int i = num; i > 0; i /= 10)
rev = rev * 10 + i % 10;
System.out.println("Reverse = " + rev);
int diff = Math.abs(num - rev);
System.out.println("Absolute difference = " + diff);
}
}
```

**Question 11**: The Greatest Common Divisor (GCD) of two integers is calculated by the continued division method. Divide the larger number by the smaller, the remainder then divides the previous divisor. The process repeats unless the remainder reaches to zero. The last divisor results in GCD.

```
import java.io.*;
class GCD{
public static void main(String args[])throws IOException{
BufferedReader br = new BufferedReader(new InputStreamReader(System.in));
int rev = 0;
System.out.print("Enter first number: ");
int a = Integer.parseInt(br.readLine());
System.out.print("Enter second number: ");
int b = Integer.parseInt(br.readLine());
int rem = a % b;
while(rem != 0){
a = b;
b = rem;
rem = a % b;
}
System.out.println("GCD = " + b);
}
}
```

**Question 12**: Write a program in Java to find the sum of the given series:**a)** s = a^{2} + a^{2}/2 + a^{2}/3 + … + a^{2}/10

```
import java.io.*;
class Series{
public static void main(String args[])throws IOException{
BufferedReader br = new BufferedReader(new InputStreamReader(System.in));
double sum = 0.0;
System.out.print("a = ");
int a = Integer.parseInt(br.readLine());
for(double i = 1.0; i <= 10.0; i++)
sum += a * a / i;
System.out.println("Sum = " + sum);
}
}
```

**Question 13**: In order to reach the top of a pole, a monkey in his first attempt reaches to a height of 5 feet and in the subsequent jumps, he slips down by 2% of the height attained in the previous jump. The process repeats and finally, the monkey reaches the top of the pole. Write a program to input height of the pole. Calculate and display the number of attempts the monkey makes to reach the top of the pole.

```
import java.io.*;
class Monkey{
public static void main(String args[])throws IOException{
BufferedReader br = new BufferedReader(new InputStreamReader(System.in));
int attempts = 1;
double a = 5.0;
System.out.print("Height of the pole = ");
double height = Double.parseDouble(br.readLine());
while(a < height){
a += 5.0;
a -= 2.0 / 100 * a;
attempts++;
}
System.out.println("Number of attempts: " + attempts);
}
}
```

**Question 14**: Write a program to input principal, rate and time. Calculate and display the amount which is compounded annually for each year by using the formula:

SI = PRT / 100 and P = P + SI

```
import java.io.*;
class Interest{
public static void main(String args[])throws IOException{
BufferedReader br = new BufferedReader(new InputStreamReader(System.in));
System.out.print("Principal: ");
double p = Double.parseDouble(br.readLine());
System.out.print("Rate: ");
double r = Double.parseDouble(br.readLine());
System.out.print("Time: ");
int t = Integer.parseInt(br.readLine());
double si = 0.0;
double amt = 0.0;
for(int i = 1; i <= t; i++){
si = p * t * r / 100;
amt = p + si;
p = amt;
}
System.out.println("Amount = " + amt);
}
}
```

**Question 15**: Write a menu-driven program to input two positive numbers m and n where m > n and perform the following tasks:

a) Find the sum of two numbers without using ‘+’ operator.

b) Find the product of two numbers without using ‘*’ operator.

c) Find the quotient and remainder of two numbers without using ‘/’ and ‘%’ operator.

```
import java.io.*;
class Menu{
public static void main(String args[])throws IOException{
BufferedReader br = new BufferedReader(new InputStreamReader(System.in));
System.out.println("1. Sum");
```

System.out.println("2. Product");

System.out.println("3. Quotient and Remainder");

System.out.print("Enter your choice: ");

int choice = Integer.parseInt(br.readLine());

switch(choice){

case 1:

System.out.print("M = ");
int m = Integer.parseInt(br.readLine());
System.out.print("N = ");
int n = Integer.parseInt(br.readLine());
if(m > n){
int sum = (m * m - n * n) / (m - n);
System.out.println("Sum = " + sum);

}

else

System.out.println("Invalid range!");

break;

case 2:
int prod = 0;

System.out.print("M = ");
m = Integer.parseInt(br.readLine());
System.out.print("N = ");
n = Integer.parseInt(br.readLine());
if(m > n){
for(int i = 1; i <= n; i++)
prod += m;
System.out.println("Product = " + prod);

}

else

System.out.println("Invalid range!");

break;

case 3:
int quo = 0;
int rem = 0;

System.out.print("M = ");
m = Integer.parseInt(br.readLine());
System.out.print("N = ");
n = Integer.parseInt(br.readLine());
if(m > n){
while(m > n){
m -= n;
quo++;
}
rem = m;
System.out.println("Quotient = " + quo);
System.out.println("Remainder = " + rem);

}

else

System.out.println("Invalid range!");

break;

default:

System.out.println("Invalid choice!");
}
}
}

**Question 16**: Write a menu-driven class to accept a number from the user and check whether it is a palindrome or a perfect number.

a) A number is palindrome which when read in reverse order is same as in the right order.

b) A number is perfect if it is equal to the sum of its factors other than the number itself.

```
import java.io.*;
class Menu2{
public static void main(String args[])throws IOException{
BufferedReader br = new BufferedReader(new InputStreamReader(System.in));
System.out.println("1. Palindrome");
System.out.println("2. Perfect");
System.out.print("Enter your choice: ");
int choice = Integer.parseInt(br.readLine());
switch(choice){
case 1:
System.out.print("Enter the number: ");
int num = Integer.parseInt(br.readLine());
int rev = 0;
for(int i = num; i != 0; i /= 10)
rev = rev * 10 + i % 10;
if(num == rev)
System.out.println(num + " is palindrome.");
else
System.out.println(num + " is not palindrome.");
break;
case 2:
int sum = 0;
System.out.print("Enter the number: ");
num = Integer.parseInt(br.readLine());
for(int i = 1; i < num; i++){
if(num % i == 0)
sum += i;
}
if(num == sum)
System.out.println(num + " is a perfect number.");
else
System.out.println(num + " is not a perfect number.");
break;
default:
System.out.println("Invalid choice!");
}
}
}
```

**Question 17**: Write a menu-driven program to accept a number from the user and check whether it is a prime number or an automorphic number.

a) A number is said to be prime if it is only divisible by 1 and itself.

b) An automorphic number is the number which is contained in the last digit(s) of its square.

Refer to Question 6 in ICSE 2010 Solved Paper.

**Question 18**: Write a menu-driven program to perform the following tasks by using the switch-case statement:

a) To print the series 0, 3, 8, 15, 24, … to n terms.

b) To find the sum of the series:

s = 1/2 + 3/4 + 5/6 + 7/8 + … + 19/20

Refer to Question 9 in ICSE 2011 Solved Paper.

**Question 19**: Using a switch statement, write a menu-driven program to:

a) Generate and display the first 10 terms of the Fibonacci series.

0, 1, 1, 2, 3, 5, …

b) Find the sum of the digits of an integer that is input.

For an incorrect choice, an appropriate error message should be displayed.

Refer to Question 8 in ICSE 2012 Solved Paper.

**Question 20**: A special two-digit number is such that when the sum of its digits is added to the product of its digits, the result is equal to the original two-digit number.

Example:

Consider the number 59.

Sum of digits = 5 + 9 = 14.

Product of its digits = 5 × 9 = 45.

Sum of the sum of digits and product of digits = 14 + 45 = 59.

Write a program to accept a two-digit number. Add the sum of its digits to the product of its digits. If the value is equal to the number input, output the message “Special 2-digit number” otherwise, output the message “Not a special 2-digit number”.

Refer to Question 5 in ICSE 2014 Solved Paper.

**Question 21**: Using the switch statement, write a menu-driven program to:

(i) To find and display all the factors of a number input by the user (including 1 and excluding the number itself).

Example:

INPUT:

n = 15

OUTPUT:

1, 3, 5

(ii) To find and display the factorial of a number input by the user. The factorial of a non-negative integer n, denoted by n!, is the product of all integers less than or equal to n.

Example:

INPUT:

n = 5

OUTPUT:

5! = 1 × 2 × 3 × 4 × 5 = 120.

For an incorrect choice, an appropriate error message should be displayed.

Refer to Question 9 in ICSE 2015 Solved Paper.

**Question 22**: Write a program to accept a number and check and display whether it is a Niven number or not. A number is said to be Niven which is divisible by its sum of digits.

Example:

Sample Input: 126.

Sum of its digits is 1 + 2 + 6 = 9, and 126 is divisible by 9.

Refer to Question 8 in ICSE 2016 Solved Paper.

**Question 23**: Write a program to accept a number and check and display whether it is a spy number or not. A number is spy if the sum of its digits equals the product of its digits.

Example: Consider the number 1124.

Sum of the digits = 1 + 1 + 2 + 4 = 8.

Product of the digits = 1 × 1 × 2 × 4 = 8.

Refer to Question 5 in ICSE 2017 Solved Paper.

**Question 24**: Using switch statement, write a menu-driven program for the following:

(i) To find and display the sum of the series given below:

S = x^{1} – x^{2} + x^{3} – x^{4} + x^{5} … – x^{20}, where x = 2.

(ii) To display the following series:

1 11 111 1111 11111

For an incorrect option, an appropriate error message should be displayed.

Refer to Question 6 in ICSE 2017 Solved Paper.

Please upload all the programs urgently because I have exams in the coming week

There are 24 programs please upload all

Please upload all the programs

Yes

This website is very useful but only for question answers nof for programs

I will soon upload programs from this chapter as well. Stay tuned.

Ye chapter ke program ko please upload Katie

Sure, I’ll soon be uploading the solutions of the programs from this chapter.

Please do it fast

Class 9 ke program

Only 19 but there are 24.. Please upload all. Thank a lot😊

Now all the 24 programs are solved. Thanks for your feedback!