A disarium number is a number in which the sum of the digits to the power of their respective position is equal to the number itself.

Example: 135 = 1^{1} + 3^{2} + 5^{3}

Hence, 135 is a disarium number.

Design a class **Disarium** to check if a given number is a disarium number or not. Some of the members of the class are given below:

**Class name:** Disarium**Data members/instance variables:**

int num: stores the number.

int size: stores the size of the number.**Methods/Member functions:**

Disarium(int n): parameterized constructor to initialize the data members num = n and size = 0.

void countDigit(): counts the total number of digits and assigns it to size.

int sumOfDigits(int n, int p): returns the sum of the digits of the number ‘n’ to the power of their respective positions ‘p’ using **recursive technique**.

void check(): checks whether the number is a disarium number and displays the result with an appropriate message.

Specify the class **Disarium** giving details of the constructor, void countDigit(), int sumOfDigits(int, int) and void check(). Define the main() function to create an object and call the functions accordingly to enable the task.

```
import java.io.*;
class Disarium{
private int num;
private int size;
public Disarium(int n){
num = n;
size = 0;
}
void countDigit(){
for(int i = num; i != 0; i /= 10)
size++;
}
public int sumOfDigits(int n, int p){
if(n < 10)
return (int)Math.pow(n, p);
else{
int t = (int)Math.pow(n % 10, p);
return t + sumOfDigits(n / 10, --p);
}
}
public void check(){
if(num == sumOfDigits(num, size))
System.out.println(num + " is a Disarium Number.");
else
System.out.println(num + " is not a Disarium Number.");
}
public static void main(String args[])
throws IOException{
InputStreamReader in = new InputStreamReader(System.in);
BufferedReader br = new BufferedReader(in);
System.out.print("Number: ");
int n = Integer.parseInt(br.readLine());
Disarium obj = new Disarium(n);
obj.countDigit();
obj.check();
}
}
```

## 2 replies on “Disarium Number ISC 2016”

Sir,a program is given which states that:

WAP in JAVA to accept some words.The program should ask for continuation.At last,display all the palindrome words among them.

Here is the solution: https://www.happycompiler.com/list-palindrome-words/