Write a program in Java to allow the user to create a square matrix of integer type.

The value of ‘m’ is entered by the user. Ensure that 3 < m < 10.

For an invalid range, display a suitable error message.

Now allow the user to fill this matrix with integers.

Finally, once the array is full, display the elements that fall below the left diagonal.

```
import java.io.*;
class BelowLeft{
public static void main(String args[])throws IOException{
BufferedReader br = new BufferedReader(new InputStreamReader(System.in));
System.out.print("M = ");
int m = Integer.parseInt(br.readLine());
if(m < 4 || m > 9){
System.out.println("Invalid range!");
return;
}
int a[][] = new int[m][m];
System.out.print("Enter integers:");
for(int i = 0; i < m; i++){
for(int j = 0; j < m; j++){
a[i][j] = Integer.parseInt(br.readLine());
}
}
System.out.println("Original Matrix:");
for(int i = 0; i < m; i++){
for(int j = 0; j < m; j++){
System.out.print(a[i][j] + "\t");;
}
System.out.println();
}
System.out.println("Elements below left diagonal:");
for(int i = 1; i < m; i++){
for(int j = 0; j < i; j++){
System.out.print(a[i][j] + "\t");
}
System.out.println();
}
}
}
```

## 2 replies on “Elements below Left Diagonal in a Square Matrix”

Sir,a program is given which states that:

Write a program to create a matrix a[][] of order (m × n) where ‘m’ is the number of rows and ‘n’ is the number of columns such that the values of both ‘m’ and ‘n’ must be greater than 2 and less than 10 .Now fill each row of the matrix uniformly by 1 or 0 alternately.

Sample Input:

M=3

N=3

Resultant matrix:

1 1 1

0 0 0

1 1 1

Here is the program to fill the matrix with zeroes and ones row-wise.