Display Alternate Digits of an Integer

Posted on by

Write a program in Java to allow the user to enter a positive integer.

Now form another integer by using the alternate digits of the given integer.

Example:
INPUT:
N = 4532
OUTPUT:
43

import java.io.*;
class Alternate{
    public static void main(String args[])throws IOException{
        BufferedReader br = new BufferedReader(new InputStreamReader(System.in));
        System.out.print("N = ");
        int n = Math.abs(Integer.parseInt(br.readLine()));
        String s = Integer.toString(n);
        String alt = "";
        for(int i = 0; i < s.length(); i += 2)
            alt += s.charAt(i);
        int result = Integer.parseInt(alt);
        System.out.println("Required Number: " + result);
    }
}

4 thoughts on “Display Alternate Digits of an Integer”

  2. Sir,can we use this procedure to create a new number by all the alternate digits of the original number?
    import java.util.Scanner;
    class AlternateDigits{
    public static void main(String args[])
    {
    Scanner sc=new Scanner(System.in);
    System.out.print(“N = “);
    int n = sc.nextInt();
    int n2=0,p=0;boolean flag=false;
    for(int i=n;i!=0;i/=10)
    {
    int dg=i%10;
    if(flag==true)
    { n2+=dg*(int)Math.pow(10,p);
    p++;
    flag=false;
    }
    else
    flag=true;
    }
    System.out.println(“New number:”+n2);
    }}

    Reply ↓

Leave a Reply